Wednesday, 14 December 2011

Logic and Philosophy, A. Hausman, H. Kahane, P. Tidman, Wadsworth, 11th ed., 2010, 13-1(2)

Prove valid:
  1. (x)(Px ⊃ Qx)
  2. (x)(Qx ⊃ Rx)
  3. Pa ¬ Rb
  4. a ≠ b
  5. Pa ⊃ Qa ......... 1 UI x/a
  6. Pa ......... 3 Simp.
  7. Qa ......... 5,6 MP
  8. Qa ⊃ Ra ......... 2 UI x/a
  9. Ra ......... 7,8 MP
  10. ¬ Rb ......... 3 Simp.
  11. a ≠ b ......... 9,10 Id

Wednesday, 7 December 2011

Logic and Philosophy, A. Hausman, H. Kahane, P. Tidman, Wadsworth, 11th ed., 2010, 13-1(1)

Prove valid:
  1. Fa (x)[Fx ⊃ (x = a)]
  2. (∃x)(Fx • Gx)
  3. Ga
  4. Fm • Gm ......... 2 EI x/m
  5. Fm ......... 4 Simp.
  6. (x)[Fx ⊃ (x = a)] ......... 1 Simp.
  7. Fm ⊃ (m = a) ......... 6 UI x/m
  8. m = a ......... 5,7 MP
  9. Gm ......... 4 Simp.
  10. Ga ......... 8,9 Id

Thursday, 1 December 2011

The Logic Book, M. Bergmann, J. Moor, J. Nelson, McGraw Hill, 2004, 10.4E, 3(d), p. 556

The solution to this problem is most likely on the Students' Solutions CD that comes with the book but the problem has caught my eye in the exercise sets pages and made me attempt my own. The task: prove that the conclusion follows.
  1. (∃x)Cx ⊃ Ch
  2. ∴(∃x)Cx ≡ Ch
  3. * ¬ [(∃x)Cx ≡ Ch] ......... AIP
  4. * ¬ {[(∃x)Cx ⊃ Ch] [Ch ⊃ (∃x)Cx]} ......... 3 BE
  5. * ¬ [(∃x)Cx ⊃ Ch] ¬ [Ch ⊃ (∃x)Cx] ......... 4 DeM
  6. * ¬ [Ch ⊃ (∃x)Cx] ......... 1,5 DS
  7. * ¬ [¬ Ch ∨ (∃x)Cx] ......... 6 MI
  8. * Ch • ¬ (∃x)Cx ......... 7 DeM
  9. * Ch ......... 8 Simp.
  10. * (∃x) Cx ......... 9 EG
  11. * ¬ (∃x)Cx ......... 8 Simp.
  12. * (∃x) Cx • ¬ (∃x)Cx ......... 10,11 Conj.
  13. ¬ ¬ [(∃x)Cx ≡ Ch] ......... 3-12 IP
  14. (∃x)Cx ≡ Ch ......... 13 DN

Thursday, 24 November 2011

The Logic Book, M. Bergmann, J. Moor, J. Nelson, McGraw Hill, 2004, 10.4E, 5(a), p. 557

We are asked to show that the two: (x)Ax and (x)(Ax • Ax) are equivalent. In other words, we must be able to go from one to the other and back.
  1. * (x)Ax ......... ACP
  2. * Ax ......... 1 UI x/x
  3. * Ax ......... 2 Rep.
  4. * Ax • Ax ......... 2,3 Conj.
  5. * (x)(Ax • Ax) ......... 4 UG
  6. (x)Ax (x)(Ax • Ax) ......... 1-6 CP
  1. * (x)(Ax • Ax) ......... ACP
  2. * Ax • Ax ......... 1 UI x/x
  3. * Ax ......... 2 Simp.
  4. * (x)Ax ......... 3 UG
  5. (x)(Ax • Ax) ⊃ (x)Ax ......... 1-4 CP